$\begin{pmatrix} 1 & 1 \ -1 & 2 \end{pmatrix}$, then $A^{-1} = \begin{pmatrix} a & b \ c & d \end{pmatrix}$ where a = b = c = d =

          $\begin{pmatrix} 1 & 1 \ -1 & 2 \end{pmatrix}$,
then
$A^{-1} = \begin{pmatrix} a & b \ c & d \end{pmatrix}$
where
a = 
b = 
c = 
d =

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

11/07/2023

Step 1

The determinant of a 2x2 matrix is given by det(A) = ad - bc. Show more…

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If A = [[1, 1], [-1, 2]] then A^(-1) = [[a, b], [c, d]] where a = b = c = d = 4 - [1 then A^(-1) = where a = b = c = d =

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