Question

If a gyroscope data shows $g_x = -0.1$, $g_y = 0.2$ and $g_z = 0.5$ rad/s with an initial pitch, roll and yaw angles, 10, 5, 90 degrees respectively. Generate a MATLAB code to define an initial quaternion and calculate the orientation after 10 seconds using quaternion kinematics equations.

          If a gyroscope data shows $g_x = -0.1$, $g_y = 0.2$ and $g_z = 0.5$ rad/s with an initial pitch, roll and yaw angles, 10, 5, 90 degrees respectively. Generate a MATLAB code to define an initial quaternion and calculate the orientation after 10 seconds using quaternion kinematics equations.
        
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If a gyroscope data shows gx = -0.1, gy = 0.2 and gz = 0.5 rad/s with an initial pitch, roll and yaw angles, 10, 5, 90 degrees respectively. Generate a MATLAB code to define an initial quaternion and calculate the orientation after 10 seconds using quaternion kinematics equations.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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If a gyroscope data shows gx = -0.1, gy = 0.2, and gz = 0.5 rad/s with initial pitch, roll, and yaw angles of 10, 5, and 90 degrees respectively, generate a MATLAB code to define an initial quaternion and calculate the orientation after 10 seconds using quaternion kinematics equations.
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Transcript

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00:01 Hi, so we have to consider the rational field that we have been given f is equals to 0, 10 z, minus of 10 y is in regards to plus into the plane of x plus y plus z is equals to 1 with this axis normal to this plane.
00:21 So using a computer algebra, we have to calculate the fast paddle wheel spins in revolution per minute, that means angular speed.
00:29 So let's get started with the solution.
00:30 So first of all, let us find the curler of f, which is given by divergence of it, that is del cross f and it is given by the formula of i, j and k.
00:43 Here it should be del by del x, del by del y, del by del z, that is value of del and here it should be the f of x term, f of y term and f of z term.
01:00 Substituting all the required values to be here, we get del cross f, this should be equals to the i, j and k.
01:09 Here it should be del by del x, del by del y, del by del z.
01:15 So here it will becomes x component is 0, y component 10 z and z components minus of 10 y.
01:24 So let's expand this along the first row.
01:27 So we are going to get iota times of del by del y of negative of 10 y minus of del by del z of 10 z negative of j, 0 minus 0 plus k, 0 minus 0 and this we have to equate it to 0.
01:46 So this will comes out equals to iota minus 10 minus 10.
01:52 This will be goes to negative of 20 iota.
01:55 So, pidal will is placed in the plane of x plus y plus z is equals to 1 with axis normal to this plane...
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