If a hydraulic system has 3000 N applied to the input piston that has a cross-sectional area of 90 cm^2, what is the pressure on the piston?
Added by Barry M.
Step 1
Given that the cross-sectional area is 90 cm^2, we need to convert it to m^2. Since 1 m = 100 cm, we can convert cm^2 to m^2 by dividing by 10,000. 90 cm^2 / 10,000 = 0.009 m^2 Show more…
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