IF A = Zax + 3ay, B = -Zaxtaz, and C = Zay + 4az, the vector in the plane containing A and C and perpendicular to B is 8ax + Z0av + 16az Tdel Cun Pnd} bac.
Added by Linda C.
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We can do this by taking the cross product of A and C: A x C = (3ay x 4az) - (Zax x Zay) = 12ax - Z^2az Now, we need to find a vector that is perpendicular to B. We can do this by taking the dot product of the vector we just found (A x C) and B: (A x C) · B = Show more…
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