00:01
Hello, in this question we are asked about that molecule which is having the high concentration of the hydrogenium ion.
00:09
So here we know that, that is, if we find out the value of the ph, only then we can find out the value.
00:21
So here we have, we know that that is ph is equal to half p -k -a value minus half of log -c.
00:31
To find out the hydrogenium ion.
00:36
So as the concentration of all the molecules it is same.
00:39
Therefore we can say that that is ph is equal to half pca value.
00:45
So now in the first part we have hcn.
00:52
So here this for hcn first we need to find out the pka value.
00:59
So pka is equal to minus log of ka.
01:03
So here minus log of ka value it is given 6 .2 multiply by 10 raised to the power minus 10.
01:10
And hence on solving this we will have 9 .21.
01:14
And therefore ph value it is equal to half of pca.
01:20
So therefore half of 9 .21.
01:24
And here we will have the value of this ph that is 4 .6.
01:37
It is there.
01:41
So therefore we know that that is for this concentration.
01:45
If we need to find out here this concentration value that will be equal to minus 10 raised to the power 10 raised to the power minus ph that is 10 raised to the power minus 4 .6 and this will become 2 .5 multiply by 10 to the power minus 5.
02:05
So this is the value because here we know that that is p h is equal to minus log of h positive concentration.
02:14
So therefore here if we find out the value of this concentration only then we can find out which is the highest concentration of the hydroniumium.
02:24
Now in the second one, now we can put directly the value into the formula.
02:31
Now here second we have hf molecule.
02:35
So for hf, first p -k -a value, k -a value it is given.
02:40
So p -k -a is equal to minus log of k -a, that is 6 .3 multiply by 10 days to the power minus 4, and this will become 3 .2.
02:51
And p -h is equal to half of p -ka, so this will become 3 .2, that is 1 .6.
03:00
And therefore, here, the concentration, h -positive or h -3 -o -positive, this will become 10 -dase to the power minus 1 .6...