8) If all the letters of the word ARRANGE are arranged in all possible ways, in how many of words we will have the A's not together and also the R's not together.
Added by Sean M.
Close
Step 1
This can be done using the formula for permutations of n objects taken r at a time, which is n!/(n-r)!. In this case, we have 7 letters, so n=7. If we arrange all 7 letters, we get 7!/(7-7)! = 7! = 5040 possible arrangements. Now, let's consider the condition Show more…
Show all steps
Your feedback will help us improve your experience
Aarti Kumari and 74 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In how many ways can the letters of the word number be arranged if the e and r must remain next to each other?
Sequences, Series, and Probability
Permutations and Combinations
How many arrangements of the letters of the word REMAND are possible if d) They have RE together in order? e) They have REM together in any order? f) R, E and M are not to be together?
Hoan N.
How many arrangements can be made out of the letters of the word 'COMMITTEE', taken all at a time such that the 4 vowels do not come together?
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD