Question

If A = 0x65 and m1 is a masking byte (both A and m1 are declared as char) Which of the following statements is incorrect? Select one: a. If m1=0xAB, then m1 | A << 2 is 0xBF b. If m1=0x53, then m1 & A >> 2 is 0x12 c. If m1=0xAB, then m1 & A << 1 is 0x8A d. None of the other has an error. All the statements are correct e. If m1=0x35, then m1 | A >> 1 is 0x37

          If A = 0x65 and m1 is a masking byte (both A and m1 are declared as char)
Which of the following statements is incorrect?
Select one:
a.
If m1=0xAB, then m1 | A << 2 is 0xBF
b.
If m1=0x53, then m1 & A >> 2 is 0x12
c.
If m1=0xAB, then m1 & A << 1 is 0x8A
d. None of the other has an error. All the statements are correct
e.
If m1=0x35, then m1 | A >> 1 is 0x37

If A = 0x65 and m1 is a masking byte (both A and m1 are declared as char)
Which of the following statements is incorrect?
Select one:
a.
If m1=0xAB, then m1 | A << 2 is 0xBF
b.
If m1=0x53, then m1 A >> 2 is 0x12
c.
If m1=0xAB, then m1 A << 1 is 0x8A
d. None of the other has an error. All the statements are correct
e.
If m1=0x35, then m1 | A >> 1 is 0x37

Added by Diana H.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Dave Kratz

Step 1

If m1 = 0xAB, then m1A << 2 is 0xBF6. m1A = 1010 1011 * 0110 0101 = 1111 1111 0110 0101 m1A << 2 = 1111 1101 1001 0100 0xBF6 = 1011 1111 0110 b. If m1 = 0x53, then m1 & A is 0x12. m1 & A = 0101 0011 & 0110 0101 = 0100 0001 0x12 = 0001 0010 c. If m1 = 0xAB, then Show more…

Show all steps

Thanks for your feedback!

If A = 0x65 and m1 is a masking byte (both A and m1 are declared as char), which of the following statements is incorrect? a. If m1 = 0xAB, then m1A << 2 is 0xBF6. b. If m1 = 0x53, then m1 & A is 0x12. c. If m1 = 0xAB, then m1 & A << 1 is 0x8A. d. None of the others have an error. All the statements are correct. e. If m1 = 0x35, then m1 | A >> 1 is 0x37.