If $F$ and $W_s$ can be neglected from the steady-state mechanical energy balance, then the equation becomes: First law of thermodynamics for an open system First law of thermodynamics for a closed system Bernoulli's equation
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Step 1: The question asks what equation results from the steady-state mechanical energy balance when $F$ (friction) and $W_s$ (shaft work) are neglected. Show more…
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The first law of thermodynamics can be described in the form of the energy balance equation, Ein - Eout = ΔEsystem. (i) Rewrite the above equation by including all the possible terms for the energy term. (ii) Which term(s) in the equation did you write as an answer for (i) that can be excluded for a closed system? (iii) Rewrite the equation you wrote as an answer for (i) for steady flow through a control volume.
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The 1st law of thermodynamics for a CV can be written: dEcv/dt = Q_cv - W_cv + Σ mi(hi + Vi^2/2 + gzi) - Σ me(he + Ve^2/2 + gze) If you simplify this equation for a STEADY flow, with ONE INLET, ONE EXIT, neglecting changes in kinetic and potential energy, for a TURBINE that MAY HAVE HEAT TRANSFER you will obtain which of the following equations? 0 = Q_cv - W_cv + (hi + Vi^2/2) - (he + Ve^2/2) Q_cv = m(hi - he) W_cv = m(hi - he) + Q_cv W_cv = (hi + Vi^2/2) - (he + Ve^2/2) The 1st law of thermo for a CV can be written: dEcv/dt = Q_cv - W_cv + Σ mi(hi + Vi^2/2 + gzi) - Σ me(he + Ve^2/2 + gze) If you simplify this equation for a STEADY flow, with ONE INLET, ONE EXIT, neglecting changes in kinetic and potential energy, for a COMPRESSOR that MAY HAVE HEAT TRANSFER you will obtain which of the following equations? 0 = Q_cv - W_cv + (hi + Vi^2/2) - (he + Ve^2/2) W_cv = (hi + Vi^2/2) - (he + Ve^2/2) W_cv = m(hi - he) + Q_cv Q_cv = m(hi - he)
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Which of the following are correct statements of the control volume formulation of the 1st law of thermo for a STEADY flow with only ONE INLET flow and ONE EXIT flow? Note, where present in the following equations: qcv = Qcv / m, wcv = Wcv / m where A refers to the area of the inlet or exit port, depending on which integral is being evaluated.
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