00:01
Solution of this question is r4b4 equal to sigma m 8 9 10 11 12 13 14 15 b 3 is equal to sigma m 4 5 6 6 7 8 9 6 7 8 9 10, 11, b2 equal to sigma m, 2, 3, 4, 5, 8, 9, 14, 15, b1 equal to sigma m, 1, 2, 4, 5, 8, 9, 14 and 15.
01:33
4 -bit gray this is here 4 -bit gray bit gray g4 g3 g2 g1 4 -bit binary is b4 b3 b2 b1 0000 0 -0 -1 here 0 -0 -0 -1 -0 -1 -0 -1 -0 -0 -0 -1 -0 -0 -1 here here 0 -1 -0 -1 -1 -0 -0 -1 -1 -1 -0 here 0 -1 -0 -0 -0 1 0 -0 -0 1 0 -1 -0.
03:33
0111 0101 0101 0101 1 at this 1101 01 01 0100 here 1 0000 1 1100 here add this 1 0100 is 011 0 is 0 0 111.
04:25
1100 is 1 0000.
04:30
1 .1 -0 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -0 is 1 -1 -1 -1 -1 -1.
04:56
Now k -map 4 for 4 b4 is this is 0 1 3 and here is 2 here 4 1 45 9 4 5 7 6 7 6 12 13 15 14 and here is 3 and here is 3 4 .3010.
06:29
This is 0 .0 .01 .11 .10.
06:37
Here 0 .01 .1110...