Question

If ln(a) = 2, ln(b) = 3, and ln(c) = 5, evaluate the following: (a) $\ln(\frac{a^{-1}}{b^{-3}c^4}) = -13$ (b) $\ln\sqrt{b^{-1}c^{-2}a^{-3}} = -\frac{19}{2}$ (c) $\frac{\ln(a^3b^{-3})}{\ln(bc)^{-4}} = $ (d) $(\ln c^4)(\ln(\frac{a}{b^{-3}})) = $

          If ln(a) = 2, ln(b) = 3, and ln(c) = 5, evaluate the following:
(a) $\ln(\frac{a^{-1}}{b^{-3}c^4}) = -13$
(b) $\ln\sqrt{b^{-1}c^{-2}a^{-3}} = -\frac{19}{2}$
(c) $\frac{\ln(a^3b^{-3})}{\ln(bc)^{-4}} = $
(d) $(\ln c^4)(\ln(\frac{a}{b^{-3}})) = $

If ln(a) = 2, ln(b) = 3, and ln(c) = 5, evaluate the following:
(a) ln((a^-1)/(b^-3c^4)) = -13
(b) ln√(b^-1c^-2a^-3) = -(19)/(2)
(c) (ln(a^3b^-3))/(ln(bc)^-4) =
(d) (ln c^4)(ln((a)/(b^-3))) =

Added by Michelle I.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Kate Smiley

Step 1

(a) ln(13) Since we are given that lnc = 5, we can substitute c with 5 in the expression ln(13): ln(13) = ln(5^2 + 3) = ln(25 + 3) = ln(28) Show more…

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