If only 0.212 g of Ca(OH)2 dissolved in enough water to give 0.152 L of aqueous solution at a given temperature, what is the Ksp value for calcium hydroxide at this temperature?
Added by Kim A.
Step 1
212 g. Given: - Mass of Ca(OH)2 = 0.212 g - Molar mass of Ca(OH)2 = 40.08 g/mol (Ca: 40.08 g/mol, O: 16.00 g/mol, H: 1.01 g/mol) Number of moles = Mass / Molar mass Number of moles = 0.212 g / 74.09 g/mol Number of moles = 0.00286 mol Show more…
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