00:01
In this question, we have been given three vertices.
00:03
We need to find out the area of the triangle pqr formed by these vertices.
00:08
Okay.
00:09
So let us see how can we find it out.
00:12
So we can, if i form a triangle here, okay.
00:17
So let's say this is my triangle.
00:20
And let's name them.
00:22
Let's say this is p.
00:23
This is q.
00:25
This is r.
00:26
Then we know that the area of triangle.
00:29
Okay pqr s so since the area of triangle pqrr is given by half of modulus of the cross product pq and prr okay so this is the formula that we are going to use here so first of all we will try to find out pq vector okay so these are the vectors here pq and we are so let's find out what is p q so this will be minus 2 -1 -3 minus 202 okay so what we will get minus minus 2 minus 2 is minus 4 1 minus 0 1 3 minus 2 1 okay and similarly we will try to find what is b r so b is minus 2 1 3 sorry this is not b first we will say subtract r minus b.
01:35
Okay.
01:36
So r is given to be 524 minus 202.
01:43
Okay.
01:44
So what this will give me? 5 minus 2, 3, then 2 and then 2.
01:49
Okay, so these are the two vector.
01:51
I will try to find out the cross product of it, pq cross pr.
01:56
Okay, so this is given by the determinant.
01:59
I cap, j, cap, k cap...