If q1 = 7 μC and q2 = -6 μC, the magnitude of the force acting on q2 from q1 is Fq2 = 62.0 N. What is the distance in cm between q1 and q2?
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0 \, N \) - \( k = 9 \times 10^9 \, Nm^2/C^2 \) - \( q1 = 7 \times 10^{-6} \, C \) - \( q2 = -6 \times 10^{-6} \, C \) - \( r \) is the distance between the charges (in meters) Show more…
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