Question

5) If sec\left(\frac{\pi}{2} - \theta\right) = 2.79, find csc $\theta$. 7) Find cot $\theta$ and sin $\theta$ if csc $\theta = \frac{9}{5}$ and cot $\theta > 0$. 9) Find sec $\theta$ and cot $\theta$ if tan $\theta = -5$ and sec $\theta > 0$. 11) Find csc $\theta$ and cos $\theta$ if sec $\theta = 2$ and cot $\theta > 0$. Verify each identity. 13) $\frac{tan^2 x}{csc x} = \frac{sin x}{cot^2 x}$

          5) If sec\left(\frac{\pi}{2} - \theta\right) = 2.79, find csc $\theta$.

7) Find cot $\theta$ and sin $\theta$
if csc $\theta = \frac{9}{5}$ and cot $\theta > 0$.

9) Find sec $\theta$ and cot $\theta$
if tan $\theta = -5$ and sec $\theta > 0$.

11) Find csc $\theta$ and cos $\theta$
if sec $\theta = 2$ and cot $\theta > 0$.

Verify each identity.

13) $\frac{tan^2 x}{csc x} = \frac{sin x}{cot^2 x}$

5) If sec((π)/(2) - θ) = 2.79, find csc θ.

7) Find cot θ and sin θ
if csc θ = (9)/(5) and cot θ > 0.

9) Find sec θ and cot θ
if tan θ = -5 and sec θ > 0.

11) Find csc θ and cos θ
if sec θ = 2 and cot θ > 0.

Verify each identity.

13) (tan^2 x)/(csc x) = (sin x)/(cot^2 x)

Added by Randy H.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Matthew Wagner

07/24/2023

Step 1

79. We know that sec\theta = \frac{1}{\cos\theta}. So, we can rewrite the given equation as \frac{1}{\cos((\pi )/(2)-\theta )}=2.79. Show more…

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If sec((pi )/(2)- heta )=2.79, find csc heta Find cot heta and sin heta if csc heta =(9)/(5) and cot heta >0. Find sec heta and cot heta if tan heta =-5 and sec heta >0. Find csc heta and cos heta if sec heta =2 and cot heta >0. Verify each identity. (tan^(2)x)/(cscx)=(sinx)/(cot^(2)x)