If the coefficient of friction between tires and road is 0.85 what is the shortest distance that a car can stop in from a velocity of 28msec?Ā¹?
Added by Paul G.
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The formula for deceleration due to friction is a = Ī¼g, where Ī¼ is the coefficient of friction and g is the acceleration due to gravity (approximately 9.8 m/sĀ²). So, a = 0.85 * 9.8 = 8.33 m/sĀ². Show moreā¦
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