Question

If the common-emitter current gain \(\beta\) for an NPN BJT in the forward-active region is equal to 66.3, then what is the common-base current gain \(\alpha\) for this transistor? Since \(\alpha\) only varies slightly, be sure to give your answer for \(\alpha\) to at least 3 decimal places!

          If the common-emitter current gain \(\beta\) for an NPN
BJT in the forward-active region is equal to 66.3,
then what is the common-base current gain \(\alpha\) for
this transistor? Since \(\alpha\) only varies slightly, be sure
to give your answer for \(\alpha\) to at least 3 decimal
places!

If the common-emitter current gain β for an NPN
BJT in the forward-active region is equal to 66.3,
then what is the common-base current gain α for
this transistor? Since α only varies slightly, be sure
to give your answer for α to at least 3 decimal
places!

Added by Ryan A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supratim Pal

Step 1

So, we have: β = IC / IB The common-base current gain (α) is defined as the ratio of the collector current (IC) to the emitter current (IE) in the forward-active region. So, we have: α = IC / IE Show more…

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If the common-emitter current gain for an NPN BJT in the forward-active region is equal to 66.3, then what is the common-base current gain a for this transistor? Since a only varies slightly, be sure to give your answer for a to at least 3 decimal places! Answer: Check