If the distance between two negative point charges is doubled, the resultant potential energy is what factor times the initial potential energy? a. 2.0 b. 4.0 c. 1/4 d. 1/2 Two point charges of values +1.4 and +2.6 C are separated by 0.80 m. What is the electrical potential at the point midway between the two point charges? (k = 8.99 x 10^9 N-m^2/C^2) a. 1.8 x 10^4 V b. 8.99 x 10^4 V
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Step 1: The potential energy of two negative point charges separated by a distance is given by \(U = \frac{-kQ_1Q_2}{r}\), where \(k\) is the Coulomb constant, \(Q_1\) and \(Q_2\) are the charges, and \(r\) is the distance between them. Show more…
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