00:01
Hi friends for the given circuit applying kirchhoff note kirchof first law on the note you can write i1 is called to i2 plus i3 applying loops law you can write l d i1 upon d t plus r1 i2 is called to emf and from equation 1 and 2 this is on loop 1 remember it you will get l d upon d t of i 2 plus i 3 is equal to r 1 i 2 is called to e or you can write l d i 2 upon d t plus l d i 3 plus r 1 i 2 plus r 1 i 2 is equal to e applying kirchap's law loop law for loop 2 minus r1 i2 plus r2 i 3 is plus q upon c is called to 0 this is is equation third applying kirchops loop's law for outer loop we will get at n, d .i .1 upon dt plus r2i3 plus q upon c is equal to e, say equation number four.
03:18
Comparing equation 2 and 4, you will get q is equal to cr1 i2 minus cr2 i3, say equation number 5.
03:41
D differentiating equation 5, you will get dq upon dt is equal to i3, cr1, d i2 upon dt, minus cr2, d i3 upon dt.
04:24
From equation 5 and 3, we will get r2 into i3 minus, just a moment.
04:50
So from 2 and 3, we can write minus r1, i2, plus, r2 i3 plus c r1 i2 i 2 minus c r2 i 3 upon c is equal to 0 so you will get minus r1 i 2 plus r2 i 2 minus r2 i 3 is equal to is called to 0.
06:04
Putting in 6, we will get cr2, d .i .3 upon d .t.
06:17
Minus i3 is equal to 0.
06:29
Dividing both the side by c...