If the human eye has an osmotic pressure of 8.00 atm at $25^{\circ} \mathrm{C}$ , what concentration of solute particles in water will provide an isotonic eyedrop solution (a solution with equal osmotic pressure)?
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Given: pi = 8.00 atm R = 0.0821 L.atm/mol.K T = 25°C = 298 K Show more…
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If the human eye has an osmotic pressure of 8.00 atm at $25^{\circ} \mathrm{C}$ what concentration of solute particles in water will provide an isotonic eye drop solution (a solution with equal osmotic pressure)?
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Analyzing Information The osmotic pressure of a dilute solution can be calculated as follows: $\pi=M R T$ $\pi=$ osmotic pressure $M=$ concentration in moles per liter $R=$ ideal gas constant $T=$ absolute temperature of the solution How does the osmotic-pressure equation compare with the ideal gas law?
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