If the Ka of the conjugate acid is 4.51 × 10-8 , what is the pKb for the base?
Added by Ramon G.
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The relationship is given by the equation: \[ K_w = K_a \times K_b \] where \( K_w \) is the ion product of water, which at 25°C is \( 1.0 \times 10^{-14} \). Show more…
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