00:01
In this question, we have to find out the molecular formula of the compound whose molecular weight given is equal to.
00:08
Molecular weight of the compound given is equal to 108 gram.
00:13
And it is also known that it is an oxide of nitrogen.
00:17
So if it is an oxide of nitrogen, it consists two atom, oxygen and nitrogen.
00:24
And the amount of nitrogen reacted is 4 .02, while oxygen present is 1 .02.
00:30
11 .48 gram.
00:32
So first of all we have to calculate its empirical formula and from empirical formula we will calculate our molecular formula.
00:39
Using empirical formula table element we have nitrogen and oxygen.
00:45
Mass of nitrogen and oxygen is given that is 4 .02 and 11 .48 and molar masses of nitrogen and oxygen are respectively for nitrogen it's 14 for oxygen it's 16.
01:00
Now the relative number of atoms, we can find out the relative number of atoms by dividing the mass and molar mass of each constituent, that is 4 .02 divided by 14, which is 0 .287 for nitrogen and 11 .48 divided by 16, which is 0 .717 for oxygen.
01:21
Now we will calculate its simplest ratio...