If the motor pulls the block m= 3kg initially at rest with a...

If the motor pulls the block m= 3kg initially at rest with a constant acceleration and moves the block a distance of 4 m in 3 sec up the incline, a) Draw the free body diagram (FBD) b) Calculate the tension (T) in the cable. Consider that friction exists between the block and incline surface with ?k = 0.4 Motor Block S ?=25°

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00:01 Hello everyone, we are going to understand this question here given in the question mass of block, mass of block that is represented by m which is 3 kilogram initial speed of of the block that is 0 and distance traveled by the block distance as is given 4 meter and time time taken t is equal to 3 second proficient of kinetic friction, mu k is equal to 0 .4 and and let the required acceleration be a.

00:57 The required acceleration that is also given, value of a that is given, that we have to calculate.

01:10 And tension in the string that we have to find.

01:12 Let the required acceleration be a.

01:22 Weight of the plot, that is vertically downward and sorry, here angle of inclination, angle of inclination of plane, theta is equal to 25 also given.

01:38 Weight of the block that is working vertically downward.

01:41 Now taking the component of weight, so component of weight perpendicular to the plane that is mg cost theta and along to incline plane that is mg sine theta.

01:57 Mg cost theta will be varies by the normal reaction and there is a tensor force due to which block is moving in upward direction so friction force will be in downward direction now applying the force balance equation now applying force balance equation force balance equation so we can write f s is equal to mu into n or that is mu into m g cross thicker that is friction force now applying the force balance equation so here upward force force along to an inclined in upward direction that is t and in downward direction that is m g sine theta minus f s is equal to m into a now taking t on one side and remaining term on other side so we can write t is equal to m a plus m g sine theta plus f s is mu mg cost theta now, substituting the value in this, no, let this is equation 1.

03:28 Now using second equation of motion, using second equation of motion, so we can write s is equal to ut plus half, 80 square.

03:53 Here value of s is given 4, initial speed of object that is given 0 plus 1 by 2 into a into value of t, that is given 3...

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