if the proton has an initial speed of 1.321x10^6 ms when it is very far away from the boron nucleus
Added by Mark B.
Step 1
Let's think step by step. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 78 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A proton collides with a Boron-11 nucleus (B^11). If the proton gets close enough (to within 7.91 fm), it will fuse with the Boron nucleus and produce three helium nuclei (3He^4): p^1_1 + B^11_5 → 3He^4_2 (A) How fast would the proton need to be moving at an initial distance of 205 fm to get to 19.8 fm from the Boron nucleus? Assume the proton comes to rest when it reaches 19.8 fm. (B) If the proton has an initial speed of 1.321 !! 10^6 m/s when it is very far away from the Boron nucleus, how close does it get to the Boron nucleus in femtometers (fm)? (C) How fast does the proton need to be moving very far away from the Boron nucleus in order to fuse with it?
Adi S.
A proton having an initial speed of 3.4 x 10^5 m/s^2 enters a uniform electric field of magnitude 6.2 x 10^9 N/C having the same direction as the proton's velocity. After a time interval of 1.2 x 10^-12 s. What is the proton's speed and how far has it travelled?
Kajal R.
Two protons are moving directly toward one another. When they are very far apart, their initial speeds are 1.70 x 104 m/s. What is the distance of closest approach?
Madhur L.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD