0:00
Out answer to this question.
00:01
In the question, rate constant k is given 0 .736, it is given at 53 .12 degrees celsius or degree centigrade and activation energy at this temperature is 31 .51 kilojoule per mole.
00:26
So we have to find what is rate constant.
00:30
Red constant.
00:32
Red constant.
00:33
At 121 .4 degrees centigrade.
00:38
So we have to find the rate constant at this temperature.
00:41
So now let us move to the solution part.
00:44
So there is a very famous expression for solving such kind of problem.
00:48
We know that log of k2 divided by k1 means rate constant at a particular temperature with the initial temperature is equal to ea, which means activation energy, 2 .303 multiplied with r multiplied by 1 divided by t1, initial temperature, 1 divided by t2, final temperature...