00:01
In this question we are discussing about an sn2 reaction.
00:04
Okay.
00:05
So here it is given that the rate of a reaction for an sn2 reaction can be written as rate is equal to rate constant multiplied by the concentration of alkyl halide multiplied by the concentration of the nucleophile.
00:21
Okay.
00:22
So here we are having an alkyl halide and the nucleophile over here is a cyano group.
00:27
Okay.
00:27
Now the initial concentration is given as the concentration of alkyl halide is equal to 0 .1 molar concentration.
00:38
We also have the concentration of the cyano group and that is equal to 0 .1 molar concentration.
00:44
Okay.
00:45
So in that case the rate is given as 1 .2 multiplied by 10 to the power negative 3 molar per second.
00:54
Okay.
00:54
Now the question is if we are having the concentration of the alkyl halide as 0 .2 which means it is doubled and for the case of the nucleophile concentration it is 0 .05 then how will the rate change? that is your question here.
01:13
Okay.
01:14
So let's see the answer for the question.
01:16
Now initially we were having the rate as rate is equal to rate constant multiplied by alkyl halide multiplied by the concentration of nucleophile.
01:26
Now the new rate...