If the sprinter from the previous problem accelerates at that rate of 4.20 m/s2 for 20 m, and then maintains that velocity for the remainder of the 100-m dash, what will be his time for the race?
Added by Christy M.
Step 1
Given constant acceleration, \(a_c = 4.20 \, m/s^2\) and distance \(d = 20 \, m\). Using the equation \(v = \sqrt{2ad}\), we get: \(v_1 = \sqrt{2 \times 4.20 \, m/s^2 \times 20 \, m} = 12.65 \, m/s\). Show more…
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If the sprinter from the previous problem accelerates at that rate for $20 \mathrm{m},$ and then maintains that velocity for the remainder of the $100-\mathrm{m}$ dash, what will be his time for the race?
If the sprinter from the previous problem accelerates at that rate for 20 m, and then maintains that velocity for the remainder of the 100-m dash, what will be his time for the race?
Christopher D.
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