Unanswered Question 5 If a 65-kg man cycles at a work rate of 900 kg.m/min, the energy expenditure in METS is:
Added by Patrick R.
Close
Step 1
First, we need to convert the work rate to watts. We know that 1 watt = 1 kg * m^2 / s^3. So, we have: 90 kg * m / min = 90 kg * m / 60 s = 1.5 kg * m / s^2 Show more…
Show all steps
Your feedback will help us improve your experience
Donna Densmore and 87 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
To set resistance on the cycle ergometer, 750 kg/m/min work rate would be ____ kps on the bike. A. 1.5 kp B. 2.5 kp C. 3.5 kp D. 4.5 kp
Madhur L.
While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 61-kg person develops a power of 73 W during a race, how fast is the person running? (Assume a running step is 1.5 m long.) m/s
Sri K.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD