00:01
Hello students, for the circuit given we can see that 5 ohm and 20 ohm registers are connected in parallel.
00:10
Therefore, r equivalent of that can be written as r1 into r2 divided by r1 plus r2.
00:18
Now substituting 5 and 20 here we get 20 into 500 divided by 20 plus 5.
00:25
From this r equivalent is 4 ohm.
00:29
Therefore, the equivalent circuit can be written as inductor 1 resistor then the equivalent resistance here.
00:40
This is 4 ohm, this is 1 ohm and this one is inductor 2 henry.
00:46
Now applying kvl to this condition voltage across inductor is given by l di by dt plus voltage across 1 ohm is given by resistor r into current i 1 into i of t plus resistor into i of t which is equal to 0.
01:15
So, this is taken by using ohm's law v is equal to ir.
01:21
Then we can be written as l di by dt plus 5 i of t 4 plus 1...