ii) \( (-2+3 i)^{6} \)
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The complex number is \(-2 + 3i\). Calculate the magnitude: \[ r = \sqrt{(-2)^2 + (3)^2} = \sqrt{4 + 9} = \sqrt{13} \] Show moreā¦
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Carry out the indicated operations. Express your results in rectangular form for those cases in which the trigonometric functions are readily evaluated without tables or a calculator. $$\left(-\frac{1}{2}+\frac{1}{2} \sqrt{3} i\right)^{6}$$
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