(II) A 22-g bullet traveling 240 m/s penetrates a 2.0-kg block of wood and emerges going 150 m/s. If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
Added by Steven H.
Step 1
The momentum of an object is given by the equation: momentum = mass x velocity. The mass of the bullet is 22 g, which is equal to 0.022 kg. The velocity of the bullet before it hits the block is 240 m/s. Therefore, the momentum of the bullet before it hits the Show more…
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(II) A $22-\mathrm{g}$ bullet traveling 210 $\mathrm{m} / \mathrm{s}$ penetrates a 2.0 -kg block of wood and emerges going 150 $\mathrm{m} / \mathrm{s}$ . If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
(II) A 23 -g bullet traveling 230 $\mathrm{m} / \mathrm{s}$ penetrates a 2.0 $\mathrm{kg}$ block of wood and emerges cleanly at 170 $\mathrm{m} / \mathrm{s}$ . If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
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