(II) A 55-g bullet traveling at 250 m/s penetrates a block of ice at 0$^\circ$C and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?
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The formula for kinetic energy is KE = 1/2 mv^2, where m is the mass and v is the velocity. So, KE = 1/2 * 0.055 kg * (250 m/s)^2 = 1718.75 J. This energy is then transferred to the ice, causing it to melt. The amount of ice that can be melted is determined by Show more…
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(II) A 55-g bullet traveling at 250 m/s penetrates a block of ice at 0°C and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?
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