(II) A typical atom has a diameter of about 1.0 $\times$ 10$^{-10}$ m. ($a$) What is this in inches? ($b$) Approximately how many atoms are along a 1.0-cm line, assuming they just touch?
Added by Theresa W.
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We know that 1 meter is equal to 39.37 inches. So, we can set up a conversion factor: 1.0 × 10^(-10) m × (39.37 inches / 1 m) = 3.937 × 10^(-9) inches So, the diameter of a typical atom is about 3.937 × 10^(-9) inches. (b) Now, we need to find out how many Show more…
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(II) A typical atom has a diameter of about $1.0 \times 10^{-10} \mathrm{m}$ . (a) What is this in inches? (b) Approximately how many atoms are there along a 1.0 -cm line?
(II) A typical atom has a diameter of about $1.0 \times 10^{-10} \mathrm{m}$ (a) What is this in inches? (b) Approximately how many atoms are there along a 1.0 -cm line?
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