Question

(II) Determine the binding energy of the last neutron in a $_{19}^{40} \mathrm{K}$ nucleus.

Name: (II) Determine the binding energy of the last neutron in a 19^40K nucleus.
Uploaded: 2021-11-03T06:03:39-08:00
Duration: 2 min 16 s
Channel: Arun Bana
Description: (II) Determine the binding energy of the last neutron in a 19^40K nucleus.

          (II) Determine the binding energy of the last neutron in a $_{19}^{40} \mathrm{K}$ nucleus.

Added by Raymond H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Arun Bana

11/03/2021

Step 1

Given that the mass of the proton is 1.007825 u, the mass of the neutron is 1.00866 u, and the nucleus $_{19}^{40} \mathrm{K}$ has 19 protons and 21 neutrons. Mass of 19 protons = 19 x 1.007825 u = 19.148675 u Mass of 21 neutrons = 21 x 1.00866 u = 21.18186 Show more…

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