II- In each item, give the standard equation of the circle satisfying the given conditions. 1. center at the origin, radius 5 2. center (4,-5), radius 3 3. center (7,6), tangent to the y-axis 4. center (-5,-4), tangent to the x-axis
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Center at the origin, radius = 4 The standard equation of a circle with center (h, k) and radius r is given by: (x - h)^2 + (y - k)^2 = r^2 In this case, the center is at the origin (0, 0) and the radius is 4. So the equation becomes: (x - 0)^2 + (y - 0)^2 = Show more…
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