00:01
Hi students in this question, two blocks as indicated in the figure is been given.
00:04
Let this be block a and this be block b.
00:07
And for the case of block a, its weight will be acting in the downward direction which is taken as wa that will be equal to the product of its mass ma into acceleration due to gravity g.
00:19
On the other hand, for the case of block b, its weight wb will be acting in the downward direction which will be equal to the product of mass mb into acceleration due to gravity.
00:30
G and in this case the tension force experience of the pulley is taken as t.
00:35
On the other hand, the frictional force is taken as f.
00:38
Now in the first part of the equation, we are asked to find out the mass of block a in order to just start moving, for which we have to first find out the force which is acting on block a, which will be equal to the value of tension force t minus static friction fs will be equal to the product of mass a into acceleration a.
00:58
Let this be equation number on the other hand, the force which is acting on block b can be taken as tension force t will be equal to mass of block b into acceleration due to gravity g minus mass of block b into acceleration a.
01:15
Let this be equation number two.
01:17
Now by substituting equation number two in equation number one, our equation reduces as mb into acceleration due to gravity g will be equal to ma plus mb into acceleration into acceleration.
01:30
A plus a value of static friction f s.
01:34
And in this question, it is given that initially the acceleration a is taken to be zero.
01:39
Thereby our equation reduces as mb into acceleration due to gravity g to be equal to static friction fs...