Question

(II) One form of mass spectrometer accelerates ions by a voltage $V$ before they enter a magnetic field $B$ . The ions are assumed to start from rest. Show that the mass of an ion is $m=q B^{2} R^{2} / 2 V,$ where $R$ is the radius of the ions' path in the magnetic field and $q$ is their charge.

Name: (II) One form of mass spectrometer accelerates ions by a voltage V before they enter a magnetic field B . The ions are assumed to start from rest. Show that the mass of an ion is m=q B^2 R^2 / 2 V, where R is the radius of the ions' path in the magnetic field and q is their charge.
Uploaded: 2021-12-03T21:53:05-08:00
Duration: 4 min 18 s
Channel: Dwijendra Rao
Description: (II) One form of mass spectrometer accelerates ions by a voltage V before they enter a magnetic field B . The ions are assumed to start from rest. Show that the mass of an ion is m=q B^2 R^2 / 2 V, where R is the radius of the ions' path in the magnetic field and q is their charge.

          (II) One form of mass spectrometer accelerates ions by a voltage $V$ before they enter a magnetic field $B$ . The ions are assumed to start from rest. Show that the mass of an ion is $m=q B^{2} R^{2} / 2 V,$ where $R$ is the radius of the ions' path in the magnetic field and $q$ is their charge.

Added by Milagros C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dwijendra Rao

12/03/2021

Step 1

Step 1: Start with the equation for centripetal force acting on the ion in the magnetic field: \[ qvB = \frac{mv^2}{R} \] Show more…

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(II) One form of mass spectrometer accelerates ions by a voltage $V$ before they enter a magnetic field $B$ . The ions are assumed to start from rest. Show that the mass of an ion is $m=q B^{2} R^{2} / 2 V,$ where $R$ is the radius of the ions' path in the magnetic field and $q$ is their charge.