Ii what mass of steam at 100circc must be added to 100 kg of...

Transcript

00:01 We have a question which says that what mass of steam at 100 degrees c must be added to 1 kg of ice at 0 degree centigrade to yield liquid water at 30 degrees centigrade so mass of steam let us say mass of a steam which is equal to which we need to find out not temperature of steam is equal to 100 degrees centigrade 100 degrees centigrade 100 degrees centigrade and one kage of ice mass of ice equal to one kgg and temperature of ice initial temperature of ice is zero degree centigrade and okay the temperature total temperature we have to reach is 30 degrees centigrade 30 degree centigrade so from principle of calibrometry we know that heat lost equal to heat gained in this case heat lost by steam will be equal to heat gained by the ice so we should write mass of steam into a specific heat capacity of steam and this will be 100 degree centigrade minus 30 degree we have to go to 30 degrees centigrade it equal to mass of ice specific heat capacity of ice from zero degrees centigrade to 20 degrees centigrade plus mass of ice will have to will be changing its shape so mass of ice and latent heat of ice plus mass of water plus specific heat capacity of oh sorry mass of water into specific heat capacity of water 20 degree oh this is 30 degrees sorry not 20 30 degrees 30 degrees and this is 30 degree minus 0 degree so this will become 70 ms specific heat capacity of steam equal to minus 30 30 mass of ice specific heat capacity of ice and this is mass of ice specific heat capacity latent heat of ice plus 30 mass of water and specific heat capacity of water okay now we will be getting liquid water yes now 70 we have to find mass of steam specific heat capacity of steam is specific heat capacity of steam we should say it is 0 .48 0 .48 calorie gram per tigate centigrade so this is 0 .48 equal to minus 30 mass of ice we have 1 kg mass of ice specific heat capacity of ice is 0 .5 plus mass of ice is one latent heat of ice is 80 calorie per kg plus 30 into mass of water mass of water will be okay mass of ice we have one kg so mass of water we have to find out first mass of water will be definitely equal to one kg itself so one kg into specific heat capacity of water we should find out a specific heat capacity of water this is 4 .186 4 .186 so we have to use calculator 17 to 17 to 0 .48 so 33 .6 mass of steam equal to minus 15 plus 80 plus 30 into 4 .186 it's 125 .58.

05:23 Mass of steam will be equal to 125 .8 plus 80 minus 15, that is 190...

Question

(II) What mass of steam at 100$^\circ$C must be added to 1.00 kg of ice at 0$^\circ$C to yield liquid water at 30$^\circ$C?

Question

(II) What mass of steam at 100$^\circ$C must be added to 1.00 kg of ice at 0$^\circ$C to yield liquid water at 30$^\circ$C?

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