(III) A light ray is incident on a flat piece of glass with index of refraction $n$ as in Fig. $23-22$ . Show that if the incident angle $\theta$ is small, the emerging ray is displaced a distance $d=t \theta(n-1) / n$ from the incident ray, where $t$ is the thickness of the glass and $\theta$ is in radians. $[\text {Hint: for }$ small $\theta, \sin \theta \approx \tan \theta \approx \theta$ in radians. $]$