Question

(iii) Consider the following reduction reactions: $E^{\circ}_{Al^{3+}/Al} = -1.66 V$ $E^{\circ}_{Sc^{3+}/Sc} = -2.08 V$ If a mixture containing $Al^{3+}/Al$ was added to a mixture containing $Sc^{3+}/Sc$, which metal would be oxidised and which would be reduced? Give an explanation for your answer. [3 marks]

Name: iii consider the following reduction reactions ecircal3al 166 v ecircsc3sc 208 v if a mixture containing al3al was added to a mixture containing sc3sc which metal would be oxidised and whi 30106
Uploaded: 2020-05-12T18:56:36-08:00
Duration: 1 min 41 s
Channel: David Collins
Description: iii consider the following reduction reactions ecircal3al 166 v ecircsc3sc 208 v if a mixture containing al3al was added to a mixture containing sc3sc which metal would be oxidised and whi 30106

          (iii) Consider the following reduction reactions:
$E^{\circ}_{Al^{3+}/Al} = -1.66 V$
$E^{\circ}_{Sc^{3+}/Sc} = -2.08 V$
If a mixture containing $Al^{3+}/Al$ was added to a mixture containing $Sc^{3+}/Sc$,
which metal would be oxidised and which would be reduced? Give an
explanation for your answer.
[3 marks]

iii consider the following reduction reactions ecircal3al 166 v ecircsc3sc 208 v if a mixture containing al3al was added to a mixture containing sc3sc which metal would be oxidised and whi 30106

Added by Javier J.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

05/12/2020

Step 1

The standard reduction potential ($E^\circ$) is a measure of the tendency of a chemical species to be reduced (gain electrons). A more positive (or less negative) $E^\circ$ indicates a greater tendency for reduction. Conversely, a more negative $E^\circ$ indicates Show more…

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(iii) Consider the following reduction reactions: $E^{\circ}_{Al^{3+}/Al} = -1.66 V$ $E^{\circ}_{Sc^{3+}/Sc} = -2.08 V$ If a mixture containing $Al^{3+}/Al$ was added to a mixture containing $Sc^{3+}/Sc$, which metal would be oxidised and which would be reduced? Give an explanation for your answer. [3 marks]