iii. Find the Laplace transform of $x(t) = e^{-t}u(t) + e^{2t}u(-t)$, and sketch the ROC. (5 marks)
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The unit step function u(t) is defined as: u(t) = 0 for t < 0 u(t) = 1 for t >= 0 So, e^(-u(t)) can be written as: e^(-u(t)) = e^(-0) = 1 Therefore, the Laplace transform of e^(-u(t)) is: L{e^(-u(t))} = L{1} = 1/s Show more…
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