00:01
Here in the question we have given that percentage error in the measurement of current and voltage are 3%, are 3%, respectively.
00:10
And we have to find maximum percentage error in the measurement of resistance.
00:17
So, we have given that we have given percentage error, percentage error of voltage, percentage error of voltage, which is equal to 3 % and also we have given percentage error of current and also we have given percentage error of current which is also equals to 3 % and we have to find percentage error percentage error in percentage error in resistance we have to find percentage error in resistance so now so now if the formula given is of type if the formula is given of the type a to the power p b to the power q divided by c to the power r divided by c to the power r, then we can write the maximum permissible error in z as del z divided by z which is equals to p, del a divided by a plus q, del b divided by b plus r, del c divided by c.
01:45
So, we use this to solve our question.
01:51
So our expression for resistance is r is equal to v divided by i.
02:00
Therefore, the maximum permissible error in r can be obtained by making use of formula for percentage errors.
02:10
So, we may write e is equal to del r by r multiplied by 100, which is equal to del v by v multiplied by 100, which is equal to del v by v multiplied by 100 plus del i by i by by 100.
02:34
Here we just made a comparison with the formula for z and made substitution at the required places like we kept p is equal to 1 and q is equal to 1 in the formula and kept r in place of z and v in place of a and i in place of b...