00:01
The question that is given over here, it says that in the year 2015, united states department of agriculture issued a report indicating a family of what? so it assumed that the distribution of food expenditures of the family for four, it follows normal distribution and the standard deviation value is given, it is $90 per month.
00:34
And so we have to find out the following questions.
00:37
First one says that we have to find what percent of the family spend more than $430 but less than $890 per month on food.
00:45
That is, we are going to find out the probability of 430 less than x less than 890.
00:54
So here we know the standard deviation value and the mean value is 890.
00:58
So if we substitute here, it is probability of 430 minus 890 divided by 90, which is less than z less than 890 minus 890 divided by 90.
01:16
So this is equal to probability of z less than zero minus probability of z less than minus 5 .111.
01:28
So this is equal to 0 .5000 minus zero.
01:32
So which is equal to 50 percentage.
01:35
So this is the probability.
01:37
And then the second one, it says that we have to find out what is the probability that x is less than 830.
01:46
So this we can write the probability of z less than 830 minus 890 divided by 90...