00:01
The mean monthly salary of a random sample of 20 college graduates under the age of 30 was found to be $1 ,320 with the standard deviation of $677.
00:16
So our sample was 1 ,320.
00:20
Our standard deviation was 677.
00:23
Assume that the distribution of salaries for all college graduates under the age of 30 is normally distributed, constructed 90 % confidence interval for mu, the population mean of monthly salaries of all college graduates under the age of 30.
00:36
So a 90 % confidence interval, we're going to take 1 ,320 plus or minus 1 .645 times 677 over the square root of 20.
00:49
That's going to give us 1 ,320 plus or minus a margin of error of 249, which gives us an interval of 1 ,071 to 1 ,569.
01:02
For part b, all other information remaining unchanged, which of the following would produce a narrow...