Question

In a cathode ray tube in an old TV, electrons are accelerated from rest with a constant acceleration of magnitude $7.03 \times 10^{13} \mathrm{m} / \mathrm{s}^{2}$ during the first $2.0 \mathrm{cm}$ of the tube's length; then they move at essentially constant velocity another $45 \mathrm{cm}$ before hitting the screen. (a) Find the speed of the electrons when they hit the screen. (b) How long does it take them to travel the length of the tube?

          In a cathode ray tube in an old TV, electrons are accelerated from rest with a constant acceleration of magnitude $7.03 \times 10^{13} \mathrm{m} / \mathrm{s}^{2}$ during the first $2.0 \mathrm{cm}$ of the tube's length; then they move at essentially constant velocity another $45 \mathrm{cm}$ before hitting the screen.
(a) Find the speed of the electrons when they hit the screen. (b) How long does it take them to travel the length of the tube?

Added by Robert B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

10/03/2022

Step 1

We can use the equation of motion: $v^2 = u^2 + 2as$, where $v$ is the final velocity, $u$ is the initial velocity (which is 0 in this case since the electrons start from rest), $a$ is the acceleration, and $s$ is the distance traveled. Given: Initial velocity, Show more…

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In a cathode ray tube in an old TV, electrons are accelerated from rest with a constant acceleration of magnitude $7.03 \times 10^{13} \mathrm{m} / \mathrm{s}^{2}$ during the first $2.0 \mathrm{cm}$ of the tube's length; then they move at essentially constant velocity another $45 \mathrm{cm}$ before hitting the screen. (a) Find the speed of the electrons when they hit the screen. (b) How long does it take them to travel the length of the tube?