Question

a larger amount of easy glide, and why? 6.5 In a cold-worked metal, a dislocation density of 1 !! 10^16 m^-2 was measured after a shear strain of 10%. Assuming that the dislocations are uniformly distributed, estimate the flow stress of this metal. Take G = 25 GPa. 6.6 Consider dislocations blocked with an average spacing of l in a copper

          a larger amount of easy glide, and why?
6.5 In a cold-worked metal, a dislocation density of 1 !! 10^16 m^-2 was measured after a shear strain of 10%. Assuming that the dislocations are uniformly distributed, estimate the flow stress of this metal. Take G = 25 GPa.
6.6 Consider dislocations blocked with an average spacing of l in a copper

a larger amount of easy glide, and why?
6.5 In a cold-worked metal, a dislocation density of 1 !! 10^16 m^-2 was measured after a shear strain of 10%. Assuming that the dislocations are uniformly distributed, estimate the flow stress of this metal. Take G = 25 GPa.
6.6 Consider dislocations blocked with an average spacing of l in a copper

Added by Derek E.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/15/2023

Step 1

We are given ρ = 1 × 1016 m−2 and G = 25 GPa = 25 × 109 Pa. We need to find τ. Show more…

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6.5 In a cold-worked metal, a dislocation density of 1 x 10^16 m^-2 was measured after a shear strain of 10%. Assuming that the dislocations are uniformly distributed, estimate the flow stress of this metal. Take G = 25 GPa. 6.6 Consider dislocations blocked with an average spacing of l in a copper.