In a customer satisfaction survey 35 of those surveyed had a...

In a customer satisfaction survey, 3/5 of those surveyed had a Japanese-made car, 2/10 had a European-made car, and 2/10 had an American-made car. Of the first group, 80% said they would buy the same make of car again, and for the other two groups, the corresponding percentages are 55% and 45%. a. What is the probability that a person who said they would buy the same make again had a Japanese-made car? [5] b. What is the probability that a person who said they would NOT buy the same make again had an American-made car?

Transcript

00:01 Hi, i'm david and i'm here to help you answer your question.

00:03 Let me bring up your question here.

00:06 Now i'm going to summarize the question by the three diagram.

00:11 So we will have here one, two and three branches.

00:17 The first one will be the japanese, the second one will be the europe, the next one will be american.

00:25 Now the first one will be three out of five for the adjoin.

00:30 Europe it will be 2 out of 10 and for the american will be 2 out of 10.

00:38 Now for japan it will be buy again and not buy again.

00:47 For the europe buy again, not buy again.

00:51 American buy again, not buy again.

00:55 Now we have for the first group 80 % said they would buy the same month again so japan here the corresponding will be 0 .2.

01:05 Now for the other two groups, the corresponding percentage will be 55 percent means that 0 .55, that will be 0 .45.

01:14 And the last one will be 0 .45.

01:18 This will be 0 .55.

01:20 And now in the part a, the question asks, let you find the probability that a person who said that they would buy the same mac again have the japanese macs so probability that, find a probability who said that buy again, given that he had the japanese car, that they would buy the same make again, had the japanese mac car, exactly.

02:00 So this probability here is just equal to here, equal to the 0 .8...

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