In a double-slit experiment, monochromatic light of wavelength 657. nm is incident on identical parallel slits of width 0.410 mm and separated by a distance of 0.750 mm. The interference pattern is observed on a screen 2.87 m from the slits. The intensity at the center of the central maximum is 7.90 mW/m². What is the intensity (in mW/m²) at a point on the screen that is 0.710 mm from the center of the central maximum? i mW/m²
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The formula for the phase difference is given by: $$\phi = \frac{2\pi}{\lambda} d \sin\theta$$ where $\lambda$ is the wavelength, $d$ is the distance between the slits, and $\theta$ is the angle to the point on the screen. Show more…
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