00:02
In the breton cycle on ts diagram it is represented something like in this way.
00:12
Let's say this is 1, 2, this is 3 and this is 4.
00:17
Now it has been given that the pressure ratio is 6 .5.
00:25
That means p2 by p1 divided by p3 by p 4.
00:32
In the equation it has been represented by pb by p a equals to p c by p d and that equals to 6 .5.
00:43
Now initially it has been given that that t1 is 298 .15 kelvin.
00:52
Now we can calculate t2 using since the process 1 2 is an adiabetic isentropic process so we can write p2 by p1 power gamma minus 1 by gamma equals to t2 by t1.
01:13
Now t1 is 298 .15 kelvin and p2 by p1 is 6 .5.
01:25
So from here and gamma the value of gamma for air is 1 .4.
01:32
So from here if we calculate t2 we will get t2 equals to 5 ,500.
01:39
So here t2 is 509 kelvin.
01:48
Now in the question it has been given that the maximum temperature is 1073 kelvin or 800 degrees celsius.
01:56
So maximum temperature will be at t3.
02:00
So here it will be 1073 kelvin...