00:01
Hello students, in this question, the intensity of the solution a and the intensity of the solution b is given.
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We are going to mix 35 cm3 of solution a with 55 cm3 of solution b.
00:14
We have to find out the transmittance percentage of the resulting solution.
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Let us consider the initial intensity of the solution which is equal to 100%.
00:25
We know that absorbance is additive in nature.
00:29
Therefore, the total absorbance will be equal to absorbance of a plus absorbance of b.
00:35
We know that absorbance is equal to log of i naught divided by i.
00:43
Substituting the equation over here that is log of i naught divided by ia plus log of i naught divided by ib.
00:56
Substituting the value log of 100 divided by 42 plus log of 100 divided by 85.
01:08
On solving this, we will get a will be equal to 0 .3767 plus 0 .0706.
01:20
On adding this we will get the absorbance value of the resulting solution which is equal to 0 .4473.
01:29
This is the absorbance value of the resulting solution...