00:01
Hi everyone, the question is saying that how many integers are contained in central deprecation peak and for the e part we have to given here that the value of d is equal to 2 multiply by a.
00:13
Okay, so what we have to find out where d is the slit separation.
00:18
What is d is the slit separation and what is a here? a is the width of either slit.
00:35
So, a is the width of the slit and b is the slit separation, that means the distance between the two slit and d is equal to 2a here that is given in the question.
00:46
So we have to find out how many number of ranges are obtained in the central direction p.
00:51
Okay, so in the central diffraction peak, in the case of, in the case of diffraction, central peak is that the central peak is twice of second maxi.
01:24
Okay, so we can say that beta note is equal to two multiply by beta origin.
01:30
Okay and x is equal to x is equal to each tense that is equal to n multiply by 2 d because this will multiply by 2 because of the twice of the center maximum okay so x is equal to n 2d lambda 22 by 2 okay so from here we can we know that t lambda 25 t is equal to beta okay, if we can compare from here.
02:01
So this is equal to beta and this is equal to a.
02:05
As given in the question, a is the width of the slit and beta is the split to the slit.
02:09
So this is equal to a here.
02:11
Okay...